API Reference

Channels.getChannelByName


Syntax

mixed channels.getChannelByName ( mixed vhost, mixed name, mixed parentChannel )

Arguments

NameTypeRequiredDefault valueDescription
vhostmixedRequirednone
namemixedRequirednone
parentChannelmixedRequirednone

Sample Response

Code examples

0 comments

Be the first to comment on getChannelByName.

Add a Comment

  • captcha